上 factor of (x y)^3-(x^3 y^3) 338099-Q17 which of the following is a factor of (x+y)^(3)-(x^(3)+y^(3))
The factors of x^3 1 y^3 3xy areAnswer Correct option is D 3xy Consider, (xy)3−(x3y3)=(xy)3−(xy)(x2−xyy2) =(xy)(xy)2−(x2−xyy2) =(xy)(x22xyy2)−(x2−xyy2)Popular Problems Algebra Divide (x^3y^3)/ (xy) x3 − y3 x − y x 3 y 3 x y Since both terms are perfect cubes, factor using the difference of cubes formula, a3 −b3 = (a−b)(a2 abb2) a 3 b 3 = ( a b) ( a 2 a b b 2) where a = x a = x and b = y b = y

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Q17 which of the following is a factor of (x+y)^(3)-(x^(3)+y^(3))
Q17 which of the following is a factor of (x+y)^(3)-(x^(3)+y^(3))-Step by step detailed factorisation of X^3 Y^3 and X^3 Y^31 solution(s) found ((xy)*(x^2xyy^2))/(xy) ((xy)*(x^2xyy^2))/(xy) See steps Step by Step Solution Step 1 x 3 y 3 Simplify ——————— x y Trying to factor as a Sum of Cubes 11 Factoring x 3 y 3 Theory A sum




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(x^3y^3)=(xy)(x^2xyy^2) This is a sum of cubes This is a semiimportant identity to know (x^3y^3)=(xy)(x^2xyy^2) Although it doesn't apply directly to this question, it's also important to know that (x^3y^3)=(xy)(x^2xyy^2) This gives us the rule (x^3y^3)=(xy)(x^2∓xyy You should be able to identify the curves x 3 y 3 = 91, x y = 1, x y = 7, x y = 13 So because of my relationship to the picture I went to investigating x y = 7 first Just to leave some breadcrumbs about this intuition the black dot is given by ( 91 1 / 3, 91 1 / 3) and this is clearly less than ( 5, 5) so it's not worthSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more
Topics Terms and topics;(A) x 2 y 2 2xy (B) x 2 y 2 – xy xy 2 (D) 3xy polynomials;Which of the following is a factor of `(xy)^3(x^3y^3)?` Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams
Not a problem Unlock StepbyStep(a) x² y² 2xy (b) x² y² xy (c) xy ^2(d) 3xy 1 See answer arunk41 is waiting for your help Add your answer and earn points rohitkgirish rohitkgirish Answer (c) xy²(3xy) please mark it as brainliest New questions in Math Origi(c) cumulative frequency(d) rangeThe mean of ten items is 17 and if each itemisX^3y^3= This deals with factoring multivariable polynomials Overview;




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Stepbystep explanation Now, (x y)3 – (x3 y3) = (x y) – (x y) (x2– xy y2) using identity, a3 b3 = (a b) (a2 ab b2) = (x y) (x y)2 (x2 xy y2) = (x y) (x2 y2 2xy x2 xy y2) using identity, (a b)2 = a2 b2 2 ab) = (x y) (3xy) Hence, one of the factor(x^3y^3)/(xy) This deals with factoring binomials as the sum or difference of cubes Overview;2 solution(s) found d=0 d=0 x=0 x=0 See steps Step by Step Solution Step by step solution Step 1 Trying to factor as a Sum of Cubes 11 Factoring x 3 y 3 Theory A sum of two perfect cubes, a 3 b 3 can be factored



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Topics Terms and topics;Algebra Factor (xy)^3 (xy)^3 (x y)3 − (x − y)3 ( x y) 3 ( x y) 3 Since both terms are perfect cubes, factor using the difference of cubes formula, a3 −b3 = (a−b)(a2 abb2) a 3 b 3 = ( a b) ( a 2 a b b 2) where a = xy a = x y and b = x− y b = x y(x^3y^3)dxxy^2dy=0 This deals with factoring binomials as the sum or difference of cubes Overview;




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Algebra Polynomials and Factoring Special Products of Polynomials 1 Answer Nghi N #x^3 y^3 = (x y)(x^2 xy y^2)# Answer link Related questions What are the Special Products of Polynomials?D x 2 d 2 y = (y 2 − 2 x) 3 1 2 x 2 y 2 − 1 6 x y − 2 x 4 y − 2 x y 4 Use implicit differentiation to find the largest yvalue in the loop of the Folium of Descartes, which is given by x^3 y^3Factor (x^3y^3z^3 ) WolframAlpha Rocket science?




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We can write this expression as x^3(2y)^3 The formula for factorizing the Difference of two Cubes is a^3−b^3=(a−b)(a^2abb^2) In x^3(2y)^3, a=x b=2y x^3(2y)^3 = (x2y)*(x^2(x*2y)(2y)^2) = color(green)( (x2y)*(x^22xy4y^2) As we cannot factorize any of the factors further, we can say that we have factorised x^38y^3 completely x^3(xy)^3=(2xy)(x^2xyy^2) Here, we can use the identity a^3b^3=(ab)(a^2abb^2) Hence x^3(xy)^3 = (x(xy))(x^2x(xy)(xy)^2) = (2xy)(x^2x^2xyx^22xyy^2) = (2xy)(x^2xyy^2) Algebra Polynomials and Factoring Factor Polynomials Using How do you factor #x^3 y^3#?




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